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4z^2-7z-11=0
a = 4; b = -7; c = -11;
Δ = b2-4ac
Δ = -72-4·4·(-11)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-15}{2*4}=\frac{-8}{8} =-1 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+15}{2*4}=\frac{22}{8} =2+3/4 $
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